3). 27 pangkat 4-x = 4 pangkat 3x+2
4). 16 pangkat 4-3x = 1 per 8 pangkat x+3
4). 16 pangkat 4-3x = 1 per 8 pangkat x+3
[tex] {27}^{4 - x} = {4}^{3x + 2} \\ {3}^{3(4 - x) } = {2}^{2(3x + 2)} \\ {3}^{12 - 3x} = {2}^{6x + 4} [/tex]
Jawaban:
[tex] {16}^{4 - 3x} = { \frac{1}{8} }^{x + 3} \\ {2}^{4(4 - 3x)} = { \frac{1}{ {2}^{3} } }^{x + 3} \\ {2}^{(16-12x)} = 2^{ - 3(x + 3)} \\ {2}^{(16-12x)} = 2^{ (- 3x - 9)} \\ 16 - 12x = - 3x - 9 \\ - 12x + 3x = - 9 - 16 \\ - 9x = - 25 \\ x = \frac{25}{9} [/tex]
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